20x^2-36x-16=0

Solution for 20x^2-36x-16=0 equation:

20x^2-36x-16=0

a = 20; b = -36; c = -16;
Δ = b2-4ac
Δ = -362-4·20·(-16)
Δ = 2576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2576}=\sqrt{16*161}=\sqrt{16}*\sqrt{161}=4\sqrt{161}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-4\sqrt{161}}{2*20}=\frac{36-4\sqrt{161}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+4\sqrt{161}}{2*20}=\frac{36+4\sqrt{161}}{40}
$